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(B) The power delivered by the reactor is $P = 300 \ MW = 300 	imes 10^6 \ J/s$.The energy released per fission is $E = 170 \ MeV = 170 	imes 10^6 \

Vedclass · Accepted Answer

$4 	imes 10^{22}$

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(B) The power delivered by the reactor is $P = 300 \ MW = 300 	imes 10^6 \ J/s$.The energy released per fission is $E = 170 \ MeV = 170 	imes 10^6 	imes 1.6 	imes 10^{-19} \ J = 2.72 	imes 10^{-11} \ J$.The power is given by $P = \frac{n E}{t}$, where $n$ is the number of atoms fissioned in time $t$.For $t = 1 \ s$, the number of atoms fissioned per second is $n_s = \frac{P}{E} = \frac{300 	imes 10^6}{2.72 	imes 10^{-11}} \approx 1.103 	imes 10^{19} \ 	ext{atoms/s}$.To find the number of atoms fissioned per hour $(3600 \ s)$, we multiply by $3600$:$n_h = 1.103 	imes 10^{19} 	imes 3600 \approx 3.97 	imes 10^{22} \ 	ext{atoms/hour}$.Rounding to the nearest significant value, we get $4 	imes 10^{22}$.

An atomic power nuclear reactor can deliver $300 \ MW$. The energy released due to the fission of each nucleus of a uranium atom $^{238}U$ is $170 \ MeV$. The number of uranium atoms fissioned per hour will be:

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