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(B) The power output of the reactor is $P = 300\ MW = 300 	imes 10^6\ J/s$.Total energy required per hour $(t = 3600\ s)$ is $E_{total} = P 	imes t

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$4 	imes 10^{22}$

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(B) The power output of the reactor is $P = 300\ MW = 300 	imes 10^6\ J/s$.Total energy required per hour $(t = 3600\ s)$ is $E_{total} = P 	imes t = 300 	imes 10^6 	imes 3600\ J$.The energy released per fission is $E_{fission} = 170\ MeV = 170 	imes 10^6 	imes 1.6 	imes 10^{-19}\ J$.The number of atoms fissioned $(N)$ is given by $N = \frac{E_{total}}{E_{fission}}$.$N = \frac{300 	imes 10^6 	imes 3600}{170 	imes 10^6 	imes 1.6 	imes 10^{-19}} \approx 3.97 	imes 10^{22} \approx 4 	imes 10^{22}$ atoms.

An atomic power nuclear reactor can deliver $300\ MW$. The energy released due to fission of each nucleus of uranium atom $^{238}U$ is $170\ MeV$. The number of uranium atoms fissioned per hour will be:

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