An atomic substance A of molar mass 12 g mo | vedclass

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(D) The density formula for a cubic unit cell is given by $d = \frac{Z 	imes M}{N_{A} 	imes a^3}$.Given values:$d = 3.0 \ g \ cm^{-3}$$M = 12 \ g \

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$4$

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(D) The density formula for a cubic unit cell is given by $d = \frac{Z 	imes M}{N_{A} 	imes a^3}$.Given values:$d = 3.0 \ g \ cm^{-3}$$M = 12 \ g \ mol^{-1}$$a = 300 \ pm = 300 	imes 10^{-10} \ cm = 3 	imes 10^{-8} \ cm$$N_{A} = 6.02 	imes 10^{23} \ mol^{-1}$Rearranging for $Z$:$Z = \frac{d 	imes N_{A} 	imes a^3}{M}$Substituting the values:$Z = \frac{3.0 	imes 6.02 	imes 10^{23} 	imes (3 	imes 10^{-8})^3}{12}$$Z = \frac{3.0 	imes 6.02 	imes 10^{23} 	imes 27 	imes 10^{-24}}{12}$$Z = \frac{3.0 	imes 6.02 	imes 27 	imes 10^{-1}}{12}$$Z = \frac{487.62 	imes 0.1}{12} = \frac{48.762}{12} \approx 4.06$The nearest integer is $4$.

An atomic substance $A$ of molar mass $12 \ g \ mol^{-1}$ has a cubic crystal structure with an edge length of $300 \ pm$. The number of atoms present in one unit cell of $A$ is $.....$ (Nearest integer). Given the density of $A$ is $3.0 \ g \ cm^{-3}$ and $N_{A} = 6.02 \times 10^{23} \ mol^{-1}$.

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