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Question

(C) The average speed is defined as the total distance divided by the total time taken.Total distance $D = 120 \ km + 120 \ km + 120 \ km = 360 \ km$.

Vedclass · Accepted Answer

$\frac{3}{\frac{1}{30} + \frac{1}{25} + \frac{1}{50}} \ km/hr$

Vedclass · Answer

(C) The average speed is defined as the total distance divided by the total time taken.Total distance $D = 120 \ km + 120 \ km + 120 \ km = 360 \ km$.Time taken for the first leg $t_1 = \frac{120}{30} = 4 \ hr$.Time taken for the return trip $t_2 = \frac{120}{25} = 4.8 \ hr$.Time taken for the final leg $t_3 = \frac{120}{50} = 2.4 \ hr$.Total time $T = t_1 + t_2 + t_3 = \frac{120}{30} + \frac{120}{25} + \frac{120}{50} \ hr$.Average speed $v_{avg} = \frac{D}{T} = \frac{120 + 120 + 120}{\frac{120}{30} + \frac{120}{25} + \frac{120}{50}}$.Dividing numerator and denominator by $120$,we get $v_{avg} = \frac{3}{\frac{1}{30} + \frac{1}{25} + \frac{1}{50}} \ km/hr$.

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