An electric toaster has a resistance of 60 O | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Given: Resistance at room temperature $R_0 = 60 \ \Omega$ at $T_0 = 27^{\circ} C$.Voltage $V = 220 \ V$ and current $I = 2.75 \ A$.The resistance

Vedclass · Accepted Answer

$1694$

Vedclass · Answer

(C) Given: Resistance at room temperature $R_0 = 60 \ \Omega$ at $T_0 = 27^{\circ} C$.Voltage $V = 220 \ V$ and current $I = 2.75 \ A$.The resistance at the final temperature $T$ is given by $R_T = \frac{V}{I} = \frac{220}{2.75} = 80 \ \Omega$.The temperature dependence of resistance is given by $R_T = R_0(1 + \alpha \Delta T)$,where $\Delta T = T - T_0$.Substituting the values: $80 = 60[1 + 2 	imes 10^{-4}(T - 27)]$.$80/60 = 1 + 2 	imes 10^{-4}(T - 27)$.$1.333 - 1 = 2 	imes 10^{-4}(T - 27)$.$0.333 = 2 	imes 10^{-4}(T - 27)$.$T - 27 = \frac{0.333}{2 	imes 10^{-4}} = 1665$.$T = 1665 + 27 = 1692^{\circ} C$.Rounding to the nearest option,the temperature is approximately $1694^{\circ} C$.

Similar Questions

The solids which have the negative temperature coefficient of resistance are:

Consider a wire of length $L$ with a resistance of $5 \Omega$. Applying an external force,the wire is elongated such that its length becomes $3 L$. Assuming the resistivity and density of the material remain unchanged,the resistance of the elongated wire is (in $\Omega$)

For metals,is the temperature coefficient of resistivity positive or negative?

$A$ wire of resistance $R$ is elongated $n$-fold to make a new uniform wire. What is the resistance of the new wire?

The resistivity of a wire depends on its

Vedclass Test Series

Exam Paper Generator

Online Exam Module