An electromagnetic wave,whose wave normal mak | vedclass

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Question

(C) The angle of incidence is $i = 45^{\circ}$.The angle of deviation is $\delta = 15^{\circ}$.The angle of refraction $r$ is given by $\delta = i - r

Vedclass · Accepted Answer

$2.1 	imes 10^8 \ m/s$

Vedclass · Answer

(C) The angle of incidence is $i = 45^{\circ}$.The angle of deviation is $\delta = 15^{\circ}$.The angle of refraction $r$ is given by $\delta = i - r$,so $r = i - \delta = 45^{\circ} - 15^{\circ} = 30^{\circ}$.According to Snell's law,$\frac{\sin i}{\sin r} = \frac{v_1}{v_2}$,where $v_1$ is the speed in air and $v_2$ is the speed in the liquid.$\frac{v_2}{v_1} = \frac{\sin r}{\sin i} = \frac{\sin 30^{\circ}}{\sin 45^{\circ}} = \frac{0.5}{1/\sqrt{2}} = \frac{1/2}{1/\sqrt{2}} = \frac{1}{\sqrt{2}}$.Therefore,$v_2 = \frac{v_1}{\sqrt{2}} = \frac{3 	imes 10^8}{\sqrt{2}} = \frac{3 	imes 10^8}{1.414} \approx 2.12 	imes 10^8 \ m/s$.Thus,the speed of the electromagnetic wave in the liquid is $2.1 	imes 10^8 \ m/s$.

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