An electron,a doubly ionized helium ion $(He^{++})$ and a proton have the same kinetic energy. The relation between their respective de-Broglie wavelengths $\lambda_{e}, \lambda_{He^{++}}$ and $\lambda_{P}$ is:
- A$\lambda_{e} < \lambda_{P} < \lambda_{He^{++}}$
- B$\lambda_{e} < \lambda_{He^{++}} = \lambda_{P}$
- C$\lambda_{e} > \lambda_{He^{++}} > \lambda_{P}$
- D$\lambda_{e} > \lambda_{P} > \lambda_{He^{++}}$
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