An electron in a hydrogen atom in its ground | vedclass

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(A) The minimum energy required to escape the atom (Ionization Energy) is $13.6 \ eV$.Given that the electron absorbs $2$ times this energy,the total

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$13.6$

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(A) The minimum energy required to escape the atom (Ionization Energy) is $13.6 \ eV$.Given that the electron absorbs $2$ times this energy,the total absorbed energy is $2 	imes 13.6 \ eV = 27.2 \ eV$.The kinetic energy of the emitted electron is calculated as: $	ext{Kinetic Energy} = 	ext{Total Absorbed Energy} - 	ext{Ionization Energy}$.$	ext{Kinetic Energy} = 27.2 \ eV - 13.6 \ eV = 13.6 \ eV$.

An electron in a hydrogen atom in its ground state absorbs $2$ times as much energy as the minimum required for it to escape from the atom. The kinetic energy of the emitted electron is ............ $eV$.

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