(B) The energy of the emitted photon is given by the Rydberg formula: $\Delta E = h c R \left( \frac{1}{n_1^2} - \frac{1}{n_2^2} \right)$.Here,the tra

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

(B) The energy of the emitted photon is given by the Rydberg formula: $\Delta E = h c R \left( \frac{1}{n_1^2} - \frac{1}{n_2^2} \right)$.Here,the transition is from $n_2 = 4$ to $n_1 = 1$.$\Delta E = R h c \left( 1 - \frac{1}{4^2} \right) = R h c \left( 1 - \frac{1}{16} \right) = \frac{15}{16} R h c$.The energy of a photon can also be expressed using its relativistic mass $m$ as $E = m c^2$.Equating the two expressions for energy: $m c^2 = \frac{15}{16} R h c$.Dividing both sides by $m c$,we get the velocity of the photon $c = \frac{15 R h}{16 m}$.

Class 12 Physics Atoms Electron Energy and Electron Energy Levels in Hydrogen Atom

Difficult

An electron in a stationary hydrogen atom jumps from the $4^{\text{th}}$ energy level to the ground level. The velocity that the photon acquired as a result of the electron transition will be ($h=$ Planck's constant,$R=$ Rydberg's constant,$m=$ mass of the photon).

MHT CET 2022 All MHT CET

A
$\frac{11 R h}{16 m}$
B
$\frac{15 R h}{16 m}$
C
$\frac{9 R h}{16 m}$
D
$\frac{13 R h}{16 m}$

Explore More

Browse All

Question Bank

All Subjects

Class 12 Questions

Class 12

Physics Questions

Chapter

Atoms

Subtopic

Electron Energy and Electron Energy Levels in Hydrogen Atom

Previous Year

MHT CET 2022 Paper All MHT CET years →

Energy levels $A, B$ and $C$ of a certain atom correspond to increasing values of energy, i.e., $E_A < E_B < E_C$. If $\lambda_1, \lambda_2$ and $\lambda_3$ are the wavelengths of radiations corresponding to transitions $C$ to $B, B$ to $A$ and $C$ to $A$ respectively, which of the following relations is correct?

Medium

View Solution

When a hydrogen atom transitions from $n=2$ to $n=1$, it emits a photon. The recoil speed of the atom is $\frac{x}{5} \,m/s$. Find the value of $x$. (Use: mass of hydrogen atom $= 1.6 \times 10^{-27} \,kg$)

DifficultJEE MAIN 2024

View Solution

If $13.6 \ eV$ energy is required to ionize the hydrogen atom,then the energy required to remove an electron from $n=2$ is (in $eV$)

MediumAIEEE 2002

View Solution

The ionization energy of hydrogen is $13.6 \text{ eV}$. The energy of the photon released when an electron jumps from the first excited state $(n=2)$ to the ground state of a hydrogen atom is (in $\text{ eV}$)

EasyWBJEE 2014

View Solution

An electron of a stationary hydrogen atom transits from the fourth energy level to the ground level. The velocity of the hydrogen atom acquired as a result of photon emission will be:
{ $R =$ Rydberg constant,$m =$ mass of hydrogen atom }

Difficult

View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial

For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free

For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo

An electron in a stationary hydrogen atom jumps from the $4^{\text{th}}$ energy level to the ground level. The velocity that the photon acquired as a result of the electron transition will be ($h=$ Planck's constant,$R=$ Rydberg's constant,$m=$ mass of the photon).

Similar Questions

When a hydrogen atom transitions from $n=2$ to $n=1$, it emits a photon. The recoil speed of the atom is $\frac{x}{5} \,m/s$. Find the value of $x$. (Use: mass of hydrogen atom $= 1.6 \times 10^{-27} \,kg$)

If $13.6 \ eV$ energy is required to ionize the hydrogen atom,then the energy required to remove an electron from $n=2$ is (in $eV$)

The ionization energy of hydrogen is $13.6 \text{ eV}$. The energy of the photon released when an electron jumps from the first excited state $(n=2)$ to the ground state of a hydrogen atom is (in $\text{ eV}$)

An electron of a stationary hydrogen atom transits from the fourth energy level to the ground level. The velocity of the hydrogen atom acquired as a result of photon emission will be: { $R =$ Rydberg constant,$m =$ mass of hydrogen atom }

Vedclass Test Series

Exam Paper Generator

Online Exam Module

An electron of a stationary hydrogen atom transits from the fourth energy level to the ground level. The velocity of the hydrogen atom acquired as a result of photon emission will be:
{ $R =$ Rydberg constant,$m =$ mass of hydrogen atom }