An electron microscope is operated at $40 \ kV$. The ratio of the resolving power of this microscope to another one which uses yellow light of wavelength $6 \times 10^{-7} \ m$ is:

  • A
    $9.78 \times 10^6$
  • B
    $9.78 \times 10^4$
  • C
    $9.78 \times 10^{-4}$
  • D
    $9.78 \times 10^{-6}$

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