(B) The atomic number of element $M$ is $9$,which corresponds to Fluorine $(F)$.The electronic configuration of $M$ is $1s^2 2s^2 2p^5$.To achieve a s

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(B) The atomic number of element $M$ is $9$,which corresponds to Fluorine $(F)$.The electronic configuration of $M$ is $1s^2 2s^2 2p^5$.To achieve a stable noble gas configuration $(1s^2 2s^2 2p^6)$,the element needs to gain one electron.Therefore,it forms an anion represented as $M^{-}$.