An ester (A) with molecular formula C_9H_{10} | vedclass

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Question

(A) $1$. Ester $(A)$ is $C_6H_5COOC_2H_5$ (Ethyl benzoate). $2$. Reaction with excess $CH_3MgBr$ followed by acid workup yields a tertiary alcohol: $C

Vedclass · Accepted Answer

$C_6H_5COOC_2H_5$

Vedclass · Answer

(A) $1$. Ester $(A)$ is $C_6H_5COOC_2H_5$ (Ethyl benzoate). $2$. Reaction with excess $CH_3MgBr$ followed by acid workup yields a tertiary alcohol: $C_6H_5C(OH)(CH_3)_2$. $3$. Dehydration of this alcohol with $H_2SO_4$ gives the olefin $(B)$,which is $C_6H_5-C(CH_3)=CH_2$ ($2$-phenylpropene). $4$. Ozonolysis of $(B)$ $(C_6H_5-C(CH_3)=CH_2)$ yields acetophenone $(C_6H_5COCH_3)$,which has the formula $C_8H_8O$. $5$. Acetophenone contains a methyl ketone group $(-COCH_3)$,which gives a positive iodoform test. $6$. Therefore,the ester $(A)$ is $C_6H_5COOC_2H_5$.

List-$I$ Reaction	List-$II$ Reagents
$A$. Hoffmann Degradation	$I$. Conc. $KOH, \Delta$
$B$. Clemmensen reduction	$II$. $CHCl_3, NaOH / H_3O^{+}$
$C$. Cannizzaro reaction	$III$. $Br_2, NaOH$
$D$. Reimer-Tiemann reaction	$IV$. $Zn-Hg / HCl$

An ester $(A)$ with molecular formula $C_9H_{10}O_2$ was treated with excess of $CH_3MgBr$ and the complex so formed was treated with $H_2SO_4$ to give an olefin $(B)$. Ozonolysis of $(B)$ gave a ketone with molecular formula $C_8H_8O$ which shows positive iodoform test. The structure of $(A)$ is

Similar Questions

The major product of the following reaction is

Match List-$I$ with List-$II$.

List-$I$ Reaction List-$II$ Reagents

$A$. Hoffmann Degradation $I$. Conc. $KOH, \Delta$

$B$. Clemmensen reduction $II$. $CHCl_3, NaOH / H_3O^{+}$

$C$. Cannizzaro reaction $III$. $Br_2, NaOH$

$D$. Reimer-Tiemann reaction $IV$. $Zn-Hg / HCl$

The correct option for the above reaction is

Draw structures of the following derivatives:
$(i)$ The $2,4-$dinitrophenylhydrazone of benzaldehyde
$(ii)$ Cyclopropanone oxime
$(iii)$ Acetaldehyde dimethyl acetal
$(iv)$ The semicarbazone of cyclobutanone
$(v)$ The ethylene ketal of hexan$-3-$one
$(vi)$ The methyl hemiacetal of formaldehyde

What are $X$ and $Y$ respectively in the following reactions?
$C_6H_5COOH \xrightarrow{X} C_6H_5CHO$
$C_6H_5CHO \xrightarrow[OH^-, 293 \ K]{C_6H_5COOH} Y \text{ (Major product)}$

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