What are X and Y respectively in the followin | vedclass

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(C) The first reaction is the reduction of benzoic acid $(C_6H_5COOH)$ to benzaldehyde $(C_6H_5CHO)$. This cannot be done directly with $SOCl_2$ and $

Vedclass · Accepted Answer

$(i) \ C_2H_5OH|H^+, (ii) \ DiBAL-H, (iii) \ H_2O; \ C_6H_5-CH=CH-CO-C_6H_5$

Vedclass · Answer

(C) The first reaction is the reduction of benzoic acid $(C_6H_5COOH)$ to benzaldehyde $(C_6H_5CHO)$. This cannot be done directly with $SOCl_2$ and $H_2|Ni$ (which reduces acid chlorides to aldehydes,but the conditions are specific). The standard laboratory method to reduce a carboxylic acid to an aldehyde involves converting it to an ester first,followed by reduction with $DiBAL-H$.Step $1$: $C_6H_5COOH + C_2H_5OH \xrightarrow{H^+} C_6H_5COOC_2H_5 + H_2O$ (Esterification).Step $2$: $C_6H_5COOC_2H_5 \xrightarrow{(i) \ DiBAL-H, (ii) \ H_2O} C_6H_5CHO$ (Reduction of ester to aldehyde).Thus,$X$ is $(i) \ C_2H_5OH|H^+, (ii) \ DiBAL-H, (iii) \ H_2O$.Step $3$: The second reaction is an Aldol condensation between benzaldehyde $(C_6H_5CHO)$ and acetophenone (implied,though the prompt shows $C_6H_5COOH$ as a reactant,the product $Y$ is clearly the Claisen-Schmidt condensation product,benzalacetophenone or chalcone,$C_6H_5-CH=CH-CO-C_6H_5$).Therefore,the correct option is $C$.

What are $X$ and $Y$ respectively in the following reactions?
$C_6H_5COOH \xrightarrow{X} C_6H_5CHO$
$C_6H_5CHO \xrightarrow[OH^-, 293 \ K]{C_6H_5COOH} Y \text{ (Major product)}$

Similar Questions

Arrange the following compounds in the increasing order of their reactivity towards the nucleophilic addition of $HCN$:
$1. HCHO$
$2. CH_3COCH_3$
$3. PhCOCH_3$
$4. PhCOPh$

Identify the suitable reagent for the reaction given below.
$CH_3-CO-CH_3 \xrightarrow[(ii) H_3O^+]{(i) ?} (CH_3)_3C-OH$

Arrange the following compounds in increasing order of their reactivity in nucleophilic addition reaction :
$(P)$ Benzaldehyde
$(Q)$ $p-$Tolualdehyde
$(R)$ $p-$Nitrobenzaldehyde
$(S)$ Acetophenone

Arrange the following carbonyl compounds in decreasing order of their reactivity in nucleophilic addition reaction:
$(i)$ Benzaldehyde
(ii) $p$-Nitrobenzaldehyde
(iii) Acetophenone
(iv) $p$-Methylbenzaldehyde

$Ph_2CH-C(=O)H \xrightarrow{\text{aqueous acid}} (A) (81\%) + \text{enol} (2\%) + \text{aldehyde} (17\%)$. Product $(A)$ of the above reaction will be:

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What are $X$ and $Y$ respectively in the following reactions?$C_6H_5COOH \xrightarrow{X} C_6H_5CHO$$C_6H_5CHO \xrightarrow[OH^-, 293 \ K]{C_6H_5COOH} Y \text{ (Major product)}$