An evacuated glass vessel weighs 40.0 g when | vedclass

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(D) Mass of liquid $= 135.0 - 40.0 = 95.0 \ g$Volume of the vessel $= \frac{	ext{mass of liquid}}{	ext{density of liquid}} = \frac{95.0 \ g}{0.95 \

Vedclass · Accepted Answer

$125$

Vedclass · Answer

(D) Mass of liquid $= 135.0 - 40.0 = 95.0 \ g$Volume of the vessel $= \frac{	ext{mass of liquid}}{	ext{density of liquid}} = \frac{95.0 \ g}{0.95 \ g \ mL^{-1}} = 100 \ mL = 0.1 \ L$Mass of ideal gas $= 40.5 - 40.0 = 0.5 \ g$Using the ideal gas equation $PV = nRT$,where $n = \frac{w}{M}$:$PV = \frac{w}{M} RT$$0.82 \ atm 	imes 0.1 \ L = \frac{0.5 \ g}{M} 	imes 0.082 \ L \ atm \ K^{-1} \ mol^{-1} 	imes 250 \ K$$0.082 = \frac{0.5 	imes 0.082 	imes 250}{M}$$M = \frac{0.5 	imes 0.082 	imes 250}{0.082} = 0.5 	imes 250 = 125 \ g \ mol^{-1}$

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