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(B) The mass of the ice block at any time $t$ is given by $m(t) = m_0 - \mu t$. Since the surface is frictionless and there are no external horizontal

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$\frac{m_0v}{\mu}$

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(B) The mass of the ice block at any time $t$ is given by $m(t) = m_0 - \mu t$. Since the surface is frictionless and there are no external horizontal forces,the momentum of the block is conserved. However,the velocity $v$ remains constant because there is no force acting on the block in the horizontal direction $(F = \frac{dp}{dt} = 0)$. The block melts completely when $m(t) = 0$,which occurs at time $T = \frac{m_0}{\mu}$. The distance travelled $d$ is given by the product of velocity and time: $d = v 	imes T$. Substituting $T$,we get $d = v 	imes \frac{m_0}{\mu} = \frac{m_0v}{\mu}$.

An ice block is melting at a constant rate $\left| \frac{dm}{dt} \right| = \mu$. Its initial mass is $m_0$ and it is moving with velocity $v$ on a frictionless horizontal surface. The distance travelled by it until it melts completely is:

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