An ideal gas is taken through a quasi-static process described by $P = \alpha V^2$,where $\alpha = 5 \text{ atm}/m^6$. The gas is expanded to twice its original volume of $1 \text{ m}^3$. How much work is done by the expanding gas in this process?

An ideal gas undergoes a circular cycle centered at $4 \, atm, 4 \, L$ as shown in the diagram. The maximum temperature attained in this process is close to

$A$ gas is taken through the cycle $A \to B \to C \to A$ as shown in the figure. What is the net work done by the gas in $J$?

In the cyclic process shown on the $P-V$ diagram,the magnitude of the work done is

The figure given below shows the variation in the internal energy $U$ with volume $V$ of $2.0 \text{ mole}$ of an ideal gas in a cyclic process $abcda$. The temperatures of the gas during the processes $ab$ and $cd$ are $500 \text{ K}$ and $300 \text{ K}$ respectively. The heat absorbed by the gas during the complete process is .... $J$. (Take $R = 8.3 \text{ J/mol-K}$ and $\ln 2 = 0.69$)

One mole of a gas obeying the equation of state $P(V-b)=RT$ is made to expand from a state with coordinates $(P_{1}, V_{1})$ to a state with $(P_{2}, V_{2})$ along a process that is depicted by a straight line on a $P-V$ diagram. Then, the work done is given by