An ideal transformer converts $220 V$ $AC$ to $3.3 kV$ $AC$. It transmits the power of $4.4 kW$. If the primary coil has $600$ turns,then the alternating current in the secondary coil is

$A$ transformer has $20$ turns in the primary and $100$ turns in the secondary coil. An $AC$ voltage of $V_{\text{in}} = 600 \sin 314t$ is applied to the primary terminal of the transformer. The maximum value of the secondary output voltage obtained in volts is:

In a step-up transformer, the turn ratio is $1:10$. A resistance of $200 \, \Omega$ connected across the secondary is drawing a current of $0.5 \, A$. What is the primary voltage and current?

$A$ power transformer is used to step up an alternating $e.m.f.$ of $220\,V$ to $11\,kV$ to transmit $4.4\,kW$ of power. If the primary coil has $1000$ turns,what is the current rating of the secondary (in $,A$)? Assume $100\%$ efficiency for the transformer.

$A$ step-down transformer connected to an $AC$ mains supply of $220 \, V$ is made to operate a $11 \, V, 44 \, W$ lamp. Ignoring power losses in the transformer,what is the current in the primary circuit? (In $A$)

For the given circuit,comment on the type of transformer used: