(B) The change in magnetic flux $\Delta \phi$ is given by $\Delta \phi = N A (B_2 - B_1)$.Given: $N = 100$,$A = 24\,cm^2 = 24 \times 10^{-4}\,m^2$,$R

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(B) The change in magnetic flux $\Delta \phi$ is given by $\Delta \phi = N A (B_2 - B_1)$.Given: $N = 100$,$A = 24\,cm^2 = 24 \times 10^{-4}\,m^2$,$R = 12\,\Omega$,$B_1 = 1.5\,T$,and $B_2 = -1.5\,T$.Thus,$\Delta \phi = 100 \times 24 \times 10^{-4} \times (-1.5 - 1.5) = 0.24 \times (-3) = -0.72\,Wb$.The induced charge $Q$ is given by $Q = \frac{|\Delta \phi|}{R}$.$Q = \frac{0.72}{12} = 0.06\,C$.Converting to $mC$: $0.06\,C = 60\,mC$.

Class 12 Physics Electromagnetic Induction Faraday's and Lenz's Law

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An insulated copper wire of $100$ turns is wrapped around a wooden cylindrical core of the cross-sectional area $24\,cm^2$. The two ends of the wire are connected to a resistor. The total resistance in the circuit is $12\,\Omega$. If an externally applied uniform magnetic field in the core along its axis changes from $1.5\,T$ in one direction to $1.5\,T$ in the opposite direction,the charge flowing through a point in the circuit during the change of magnetic field will be $.........\,mC$.

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$50$
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$60$
C
$40$
D
$30$

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Electromagnetic Induction

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Faraday's and Lenz's Law

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$A$ uniform magnetic field is restricted within a region of radius $r$. The magnetic field changes with time at a rate $\frac{d\vec{B}}{dt}$. Loop $1$ of radius $R > r$ encloses the region,and loop $2$ of radius $R$ is outside the region of the magnetic field as shown in the figure. Then the $e.m.f.$ generated is:

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Assertion $(A):$ The bar magnet falling vertically along the axis of the horizontal coil will have an acceleration less than $g$.
Reason $(R):$ Clockwise current is induced in the coil.

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$A$ and $B$ are two metallic rings placed at opposite sides of an infinitely long straight conducting wire as shown. If current in the wire is slowly decreased,the direction of induced current will be

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Use Lenz's law to determine the direction of induced current in the situations described by Figure:$(a)$ $A$ wire of irregular shape turning into a circular shape;$(b)$ $A$ circular loop being deformed into a narrow straight wire.

"The polarity of induced emf is such that it tends to produce a current which opposes the change in magnetic flux that produced it." This statement is known as . . . . . . law.

Assertion $(A):$ The bar magnet falling vertically along the axis of the horizontal coil will have an acceleration less than $g$.Reason $(R):$ Clockwise current is induced in the coil.

$A$ and $B$ are two metallic rings placed at opposite sides of an infinitely long straight conducting wire as shown. If current in the wire is slowly decreased,the direction of induced current will be

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Use Lenz's law to determine the direction of induced current in the situations described by Figure:
$(a)$ $A$ wire of irregular shape turning into a circular shape;
$(b)$ $A$ circular loop being deformed into a narrow straight wire.

Assertion $(A):$ The bar magnet falling vertically along the axis of the horizontal coil will have an acceleration less than $g$.
Reason $(R):$ Clockwise current is induced in the coil.