(C) Using the ideal gas equation, $\frac{P_1 V_1}{T_1} = \frac{P_2 V_2}{T_2}$.Given:$P_1 = 2\,atm$$V_1 = 60\,cm^{3}$$T_1 = 27^{\circ}C = 27 + 273 = 30

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

(C) Using the ideal gas equation, $\frac{P_1 V_1}{T_1} = \frac{P_2 V_2}{T_2}$.Given:$P_1 = 2\,atm$$V_1 = 60\,cm^{3}$$T_1 = 27^{\circ}C = 27 + 273 = 300\,K$$V_2 = 20\,cm^{3}$$T_2 = 77^{\circ}C = 77 + 273 = 350\,K$Substituting the values into the equation:$\frac{2 \times 60}{300} = \frac{P_2 \times 20}{350}$$\frac{120}{300} = \frac{P_2 \times 20}{350}$$0.4 = P_2 \times \frac{20}{350}$$P_2 = 0.4 \times \frac{350}{20} = 0.4 \times 17.5 = 7\,atm$.

Class 11 Physics Kinetic Theory of Gases Gas Laws (Charles, Boyle's, Avagadro's, Gay Lussacs and Dalton's law) and Ideal gas Equation

Medium

An insulated cylinder of volume $60\,cm^{3}$ is filled with a gas at $27^{\circ}C$ and $2$ atmospheric pressure. Then the gas is compressed making the final volume $20\,cm^{3}$ while allowing the temperature to rise to $77^{\circ}C$. The final pressure is . . . . . . atmospheric pressure.

JEE MAIN 2026 All JEE MAIN

A
$5$
B
$6$
C
$7$
D
$8$

Explore More

Browse All

Question Bank

All Subjects

Class 11 Questions

Class 11

Physics Questions

Chapter

Kinetic Theory of Gases

Subtopic

Gas Laws (Charles, Boyle's, Avagadro's, Gay Lussacs and Dalton's law) and Ideal gas Equation

Previous Year

JEE MAIN 2026 Paper All JEE MAIN years →

Hydrogen gas and oxygen gas have a volume of $1 \, cm^3$ each at $N.T.P$. Which of the following statements is correct?

Medium

View Solution

$A$ gas at absolute temperature $300\,K$ has pressure $P = 4 \times 10^{-10}\,N/m^2$. Given the Boltzmann constant $k = 1.38 \times 10^{-23}\,J/K$,the number of molecules per $cm^3$ is of the order of:

Medium

View Solution

What is Boltzmann's constant?

Medium

View Solution

The pressure $P$,volume $V$,and temperature $T$ of a gas in jar $A$ are given. The gas in another jar $B$ is at pressure $2P$,volume $V/4$,and temperature $T/4$. What is the ratio of the number of molecules in jar $A$ to jar $B$?

MediumMHT CET 2025

View Solution

Pressure of an ideal gas,contained in a closed vessel,is increased by $0.4 \%$ when heated by $1^{\circ} C$. Its initial temperature must be

MediumJEE MAIN 2025

View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial

For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free

For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo

An insulated cylinder of volume $60\,cm^{3}$ is filled with a gas at $27^{\circ}C$ and $2$ atmospheric pressure. Then the gas is compressed making the final volume $20\,cm^{3}$ while allowing the temperature to rise to $77^{\circ}C$. The final pressure is . . . . . . atmospheric pressure.

Similar Questions

Hydrogen gas and oxygen gas have a volume of $1 \, cm^3$ each at $N.T.P$. Which of the following statements is correct?

$A$ gas at absolute temperature $300\,K$ has pressure $P = 4 \times 10^{-10}\,N/m^2$. Given the Boltzmann constant $k = 1.38 \times 10^{-23}\,J/K$,the number of molecules per $cm^3$ is of the order of:

What is Boltzmann's constant?

The pressure $P$,volume $V$,and temperature $T$ of a gas in jar $A$ are given. The gas in another jar $B$ is at pressure $2P$,volume $V/4$,and temperature $T/4$. What is the ratio of the number of molecules in jar $A$ to jar $B$?

Pressure of an ideal gas,contained in a closed vessel,is increased by $0.4 \%$ when heated by $1^{\circ} C$. Its initial temperature must be

Vedclass Test Series

Exam Paper Generator

Online Exam Module