An iron cube of 10, cm sides is hammered into | vedclass

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(B) The volume of the iron cube is $V = (	ext{side})^3 = 10\, cm 	imes 10\, cm 	imes 10\, cm = 1000\, cm^3$.When the cube is hammered into a rectan

Vedclass · Accepted Answer

$20\, cm, 100\, cm$

Vedclass · Answer

(B) The volume of the iron cube is $V = (	ext{side})^3 = 10\, cm 	imes 10\, cm 	imes 10\, cm = 1000\, cm^3$.When the cube is hammered into a rectangular sheet, the volume remains constant.Let the sides of the rectangular sheet be $x$ and $5x$ (since the ratio is $1:5$).The thickness of the sheet is $0.5\, cm$.The volume of the rectangular sheet is given by $	ext{length} 	imes 	ext{width} 	imes 	ext{thickness} = x 	imes 5x 	imes 0.5 = 2.5x^2$.Equating the volumes: $2.5x^2 = 1000$.$x^2 = \frac{1000}{2.5} = 400$.$x = \sqrt{400} = 20\, cm$.Therefore, the sides are $x = 20\, cm$ and $5x = 5 	imes 20 = 100\, cm$.

An iron cube of $10\, cm$ sides is hammered into a rectangular sheet of thickness $0.5\, cm$. If the sides of the sheet are in the ratio $1:5$, the sides (in $cm$) are:

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