An object of height 1.5 cm is placed on the | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Given: Object height $h_o = 1.5 \ cm$,Focal length $f = +25 \ cm$ (for convex lens),Image distance $v = +75 \ cm$ (real image formed by a single l

Vedclass · Accepted Answer

$3$

Vedclass · Answer

(B) Given: Object height $h_o = 1.5 \ cm$,Focal length $f = +25 \ cm$ (for convex lens),Image distance $v = +75 \ cm$ (real image formed by a single lens is inverted and on the opposite side).Using the lens formula: $\frac{1}{f} = \frac{1}{v} - \frac{1}{u}$.$\frac{1}{25} = \frac{1}{75} - \frac{1}{u} \Rightarrow \frac{1}{u} = \frac{1}{75} - \frac{1}{25} = \frac{1-3}{75} = -\frac{2}{75}$.So,$u = -37.5 \ cm$.Magnification $m = \frac{h_i}{h_o} = \frac{v}{u}$.$h_i = h_o 	imes \frac{v}{u} = 1.5 	imes \frac{75}{-37.5} = 1.5 	imes (-2) = -3 \ cm$.The size (magnitude) of the image is $3 \ cm$.

An object of height $1.5 \ cm$ is placed on the axis of a convex lens of focal length $25 \ cm$. $A$ real image is formed at a distance of $75 \ cm$ from the lens. The size of the image will be........$cm$.

Similar Questions

An object is placed in front of a convex lens,and an image of height $8 \, cm$ is formed. When the lens is moved to a new position,the image height becomes $2 \, cm$. Find the height of the object in $cm$.

The power of a biconvex lens is $10 \; D$ and the radius of curvature of each surface is $10 \; cm$. The refractive index of the material of the lens is:

$A$ double convex lens has power $P$ and same radii of curvature $R$ of both the surfaces. The radius of curvature of a surface of a plano-convex lens made of the same material with power $1.5P$ is ......$R$.

The dispersive powers of the glasses of lenses used in an achromatic pair are in the ratio $5 : 3$. If the focal length of the concave lens is $15 \ cm$,then the nature and focal length of the other lens would be:

The formation of a real image using a biconvex lens is shown below:
If the whole setup is immersed in water without disturbing the object and the screen positions,what will one observe on the screen?

Vedclass Test Series

Exam Paper Generator

Online Exam Module