An object of mass 4.237 , g occupies a volume | vedclass

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Question

(A) Given mass $m = 4.237 \, g$ (which has $4$ significant figures).Given volume $V = 1.72 \, cm^3$ (which has $3$ significant figures).Density $\rho

Vedclass · Accepted Answer

$2.46$

Vedclass · Answer

(A) Given mass $m = 4.237 \, g$ (which has $4$ significant figures).Given volume $V = 1.72 \, cm^3$ (which has $3$ significant figures).Density $\rho = \frac{m}{V} = \frac{4.237 \, g}{1.72 \, cm^3} \approx 2.46337 \, g \, cm^{-3}$.According to the rules of significant figures,the result of division should have the same number of significant figures as the measurement with the least number of significant figures.Since $1.72$ has $3$ significant figures,the final answer must be rounded to $3$ significant figures.Therefore,the density is $2.46 \, g \, cm^{-3}$.

An object of mass $4.237 \, g$ occupies a volume of $1.72 \, cm^3$. The density of the object to appropriate significant figures is ......... $g \, cm^{-3}$.

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