(A) According to the law of conservation of mechanical energy,the potential energy at the top is converted into kinetic energy at the bottom.Since bot

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Both will reach the ground with the same speed.

(A) According to the law of conservation of mechanical energy,the potential energy at the top is converted into kinetic energy at the bottom.Since both objects start from the same height $h$,their initial potential energy is $mgh$.At the bottom,this energy is converted into kinetic energy: $mgh = \frac{1}{2}mv^2$.Solving for speed $v$,we get $v = \sqrt{2gh}$.Since $v$ depends only on $g$ and $h$,both objects will reach the ground with the same speed.Therefore,the correct option is $A$.

Class 11 Physics Work, Energy, Power and Collision Work Energy Theorem and Conservation of Mechanical Energy

Easy

An object starts sliding on a frictionless inclined plane,and from the same height,another object starts falling freely. Which of the following statements is correct?

A
Both will reach the ground with the same speed.
B
Both will reach the ground with the same acceleration.
C
Both will reach the ground in the same time.
D
None of the above.

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Work, Energy, Power and Collision

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Work Energy Theorem and Conservation of Mechanical Energy

Explain the work-energy theorem.

Medium

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$A$ block of mass $1\,kg$ slides on a rough horizontal surface. If the speed of the block decreases from $10\,m/s$ to $8\,m/s$,the thermal energy developed in this process is .................. $J$.

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$A$ body of mass $0.5\, kg$ travels on a straight-line path with velocity $v = (3x^2 + 4)\, m/s$. The net work done by the force during its displacement from $x = 0$ to $x = 2\, m$ is $.......J$.

MediumJEE MAIN 2022

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The system shown in the figure is released from rest. The pulley and spring are massless,and friction is absent everywhere. The speed of the $5 \, kg$ block when the $2 \, kg$ block leaves contact with the ground is (take the force constant of the spring $k = 40 \, N/m$ and $g = 10 \, m/s^2$):

Difficult

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The velocity-time graph for a body of mass $10\, kg$ is shown in the figure. The work done on the body in the first two seconds of the motion is ................ $J$.

DifficultJEE MAIN 2016

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An object starts sliding on a frictionless inclined plane,and from the same height,another object starts falling freely. Which of the following statements is correct?

Similar Questions

Explain the work-energy theorem.

$A$ block of mass $1\,kg$ slides on a rough horizontal surface. If the speed of the block decreases from $10\,m/s$ to $8\,m/s$,the thermal energy developed in this process is .................. $J$.

$A$ body of mass $0.5\, kg$ travels on a straight-line path with velocity $v = (3x^2 + 4)\, m/s$. The net work done by the force during its displacement from $x = 0$ to $x = 2\, m$ is $.......J$.

The system shown in the figure is released from rest. The pulley and spring are massless,and friction is absent everywhere. The speed of the $5 \, kg$ block when the $2 \, kg$ block leaves contact with the ground is (take the force constant of the spring $k = 40 \, N/m$ and $g = 10 \, m/s^2$):

The velocity-time graph for a body of mass $10\, kg$ is shown in the figure. The work done on the body in the first two seconds of the motion is ................ $J$.

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