An optically active alkyl bromide C_4H_9Br re | vedclass

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(A) The optically active alkyl bromide $C_4H_9Br$ is $2$-bromobutane.Reaction of $2$-bromobutane with ethanolic $KOH$ (dehydrohalogenation) gives but-

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Haloform test

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(A) The optically active alkyl bromide $C_4H_9Br$ is $2$-bromobutane.Reaction of $2$-bromobutane with ethanolic $KOH$ (dehydrohalogenation) gives but-$2$-ene as the major product $[A]$.Reaction of but-$2$-ene $[A]$ with $Br_2$ yields $2,3$-dibromobutane $[B]$.Reaction of $2,3$-dibromobutane $[B]$ with alcoholic $KOH$ followed by $NaNH_2$ (dehydrohalogenation) yields but-$2$-yne $[C]$.Hydration of but-$2$-yne $[C]$ in the presence of $HgSO_4/H_2SO_4$ (Kucherov's reaction) yields butanone $(CH_3COCH_2CH_3)$, which is a methyl ketone.Methyl ketones are confirmed by the Haloform test (specifically the Iodoform test).

List-$I$	List-$II$
$A$. $C_6H_6 + CO + HCl \xrightarrow{AlCl_3} C_6H_5CHO$	$a$. Gattermann-Koch reaction
$B$. $C_6H_5CH_3 \xrightarrow{CrO_2Cl_2} C_6H_5CHO$	$b$. Etard reaction
$C$. $C_6H_5CH_2Br + CH_3Br \xrightarrow{Na/ether} C_6H_5CH_2CH_3$	$c$. Wurtz-Fittig reaction
$D$. $C_6H_6 + (CH_3)_2C = CH_2 \xrightarrow{H_2SO_4} C_6H_5C(CH_3)_3$	$d$. Friedel-Crafts alkylation

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