An organ pipe of length $L$ open at both ends is found to vibrate in its first harmonic when sounded with a tuning fork of $480 \ Hz$. What should be the length of a pipe closed at one end,so that it also vibrates in its first harmonic with the same tuning fork?
- A$L/2$
- B$L$
- C$2L$
- D$L/4$
Explore More
Similar Questions
$A$ tuning fork is vibrating at $250\, {Hz}$. The length of the shortest closed organ pipe that will resonate with the tuning fork will be ..... ${cm}$.
(Take speed of sound in air as $340\, {ms}^{-1}$)
(Take speed of sound in air as $340\, {ms}^{-1}$)
The fundamental frequency in an open organ pipe is equal to the third harmonic of a closed organ pipe. If the length of the closed organ pipe is $20 \ cm$,the length of the open organ pipe is .... $cm$.
MediumNEET 2018
View SolutionFor a certain organ pipe, three successive resonance frequencies are observed at $425 \,Hz$, $595 \,Hz$, and $765 \,Hz$, respectively. The length of the pipe is (speed of sound in air $= 340 \,m/s$). (in $\,m$)
Air columns in two identical tubes are vibrating. Tube $A$ has one end closed and tube $B$ has both ends open. Neglecting end correction,the ratio of the fundamental frequency of the air column in tube $A$ to that in tube $B$ is
The harmonics which are present in a pipe open at one end are
Easy
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo