An organic compound $A$ on reduction gives compound $B$,which on reaction with trichloromethane and caustic potash forms $C$. The compound $C$ on catalytic reduction gives $N$-methylbenzenamine. The compound $A$ is,

  • A
    Nitrobenzene
  • B
    Nitromethane
  • C
    Methanamine
  • D
    Benzenamine

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Similar Questions

$(a) \, CH_3CONH_2 + KOH + Br_2 \rightarrow$
$(b) \, CH_3COOH + \text{Soda lime} \rightarrow$
$(c) \, CH_3COOAg + Br_2 \rightarrow$
What is the common feature in the above three reactions?

Write $IUPAC$ names of the following compounds and classify them into primary,secondary,and tertiary amines.
$(i)$ $(CH_3)_2CHNH_2$
$(ii)$ $CH_3(CH_2)_2NH_2$
$(iii)$ $CH_3NHCH(CH_3)_2$
$(iv)$ $(CH_3)_3CNH_2$
$(v)$ $C_6H_5NHCH_3$
$(vi)$ $(CH_3CH_2)_2NCH_3$
$(vii)$ $m-BrC_6H_4NH_2$

Primary and secondary amines can be distinguished by $:-$

$A$ given nitrogen-containing aromatic compound $A$ reacts with $Sn/HCl,$ followed by $HNO_2$ to give an unstable compound $B$. $B,$ on treatment with phenol,forms a beautiful coloured compound $C$ with the molecular formula $C_{12}H_{10}N_2O.$ The structure of compound $A$ is

$A$ is a neutral organic compound $(M.F.: C_8H_9ON)$. On treatment with aqueous $Br_2 / HO^{(-)}$, $A$ forms a compound $B$ which is soluble in dilute acid. $B$ on treatment with aqueous $NaNO_2 / HCl$ $(0-5^{\circ}C)$ produces a compound $C$ which on treatment with $CuCN / NaCN$ produces $D$. Hydrolysis of $D$ produces $E$ which is also obtainable from the hydrolysis of $A$. $E$ on treatment with acidified $KMnO_4$ produces $F$. $F$ contains two different types of hydrogen atoms. The structure of $A$ is

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