An organic compound gave $C = 92.31\%$ and $H = 7.69\%$. If the molecular weight of the compound is $78$,its molecular formula is

  • A
    $C_6H_6$
  • B
    $C_7H_7$
  • C
    $C_6H_{18}$
  • D
    $C_8H_{20}$

Explore More

Similar Questions

$A$ compound contains $2.8\%$ $Fe$ by mass. If the compound contains a single $Fe$ atom in its one molecule,then the molar mass $(g/mol)$ of the compound is $(Fe = 56\, amu)$.

Difficult
View Solution

An organic compound having molecular mass $60$ is found to contain $C = 20\%$,$H = 6.67\%$,and $N = 46.67\%$,while the rest is oxygen. On heating,it gives $NH_3$ along with a solid residue. The solid residue gives a violet color with alkaline copper sulphate solution. The compound is:

Haemoglobin contains $0.33 \%$ of iron by mass. The molecular mass of haemoglobin is $67200$. The number of iron atoms present in one molecule of haemoglobin is: (Atomic mass of $Fe = 56$)

$0.48 \ g$ of an organic compound on complete combustion produced $0.22 \ g$ of $CO_2$. The percentage of $C$ in the given organic compound is

$A$ protein $'A'$ contains $0.30\, \%$ of glycine (molecular weight $75$). The minimum molar mass of the protein $'A'$ is $.......\, \times 10^{3} \, g\, mol^{-1}$ [nearest integer]

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo