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(B) When a capacitor of capacitance $C$ is charged by a battery of voltage $V$,the total energy supplied by the battery is $W = QV = (CV)V = CV^2$.The

Vedclass · Accepted Answer

Half the energy supplied is stored in the capacitor.

Vedclass · Answer

(B) When a capacitor of capacitance $C$ is charged by a battery of voltage $V$,the total energy supplied by the battery is $W = QV = (CV)V = CV^2$.The energy stored in the capacitor is $U = \frac{1}{2}CV^2$.Comparing these,the energy stored is exactly half of the total energy supplied by the battery.The remaining half of the energy is dissipated as heat in the connecting wires or internal resistance of the circuit.

An uncharged capacitor is connected to a battery. On charging the capacitor,

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