If $\frac{\tan 3A}{\tan A} = a$,then $\frac{\sin 3A}{\sin A}$ is equal to

  • A
    $\frac{2a}{a+1}$
  • B
    $\frac{2a}{a-1}$
  • C
    $\frac{a}{a+1}$
  • D
    $\frac{a}{a-1}$

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