Area of a right triangle $=$ ...........
- A$\frac{3}{2} \times$ product of the sides forming the right angle
- B$\frac{1}{2} \times$ product of the sides forming the right angle
- C$\frac{1}{5} \times$ product of the sides forming the right angle
- D$\frac{1}{3} \times$ product of the sides forming the right angle
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Similar Questions
State whether each of the following statements is true or false:
$(1)$ In a square,if the length of each side is $20 \, cm$,then the length of its diagonal is $20 \sqrt{2} \, cm$.
$(2)$ If each side of an equilateral triangle is doubled,the area of the triangle is twice the area of the original triangle.
$(1)$ In a square,if the length of each side is $20 \, cm$,then the length of its diagonal is $20 \sqrt{2} \, cm$.
$(2)$ If each side of an equilateral triangle is doubled,the area of the triangle is twice the area of the original triangle.
Medium
View SolutionWrite True or False and justify your answer.
The area of a triangle with base $4 \, \text{cm}$ and height $6 \, \text{cm}$ is $24 \, \text{cm}^2$.
The area of a triangle with base $4 \, \text{cm}$ and height $6 \, \text{cm}$ is $24 \, \text{cm}^2$.
Easy
View SolutionArea of a square $= (........... )^{2}.$
Easy
View SolutionThe area of an isosceles triangle having base $2 \, cm$ and the length of one of the equal sides $4 \, cm$ is
Medium
View SolutionIn quadrilateral $ABCD$,$AB = 9 \, cm$,$BC = 13 \, cm$,$CD = 14 \, cm$,$DA = 12 \, cm$,and $BD = 15 \, cm$. Find the area of quadrilateral $ABCD$ in $cm^2$.
Medium
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