The area under a velocity-time graph is equal | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The area under a velocity$-$time graph represents the displacement of the object.Velocity is defined as the rate of change of displacement $(v = \

Vedclass · Accepted Answer

magnitude of the displacement of the body

Vedclass · Answer

(B) The area under a velocity$-$time graph represents the displacement of the object.Velocity is defined as the rate of change of displacement $(v = \frac{ds}{dt})$.Therefore,the displacement $(s)$ can be calculated by integrating the velocity with respect to time: $s = \int v \, dt$.Geometrically,this integral corresponds to the area enclosed between the velocity$-$time curve and the time axis.If the motion is in a straight line without changing direction,the magnitude of displacement is equal to the distance travelled. However,in general,the area under the velocity$-$time graph represents the magnitude of the displacement.

The area under a velocity$-$time graph is equal to the

Similar Questions

State whether the following statement is true or false:
$A$ body is said to be at rest if it does not change its position with respect to its reference point.

The area under the velocity$-$time graph gives the value of

Draw a velocity versus time graph of a stone thrown vertically upwards and then coming downwards after attaining the maximum height.

What is the difference between uniform motion in a straight line and uniform circular motion?

Can the displacement of a particle be zero when the distance travelled is not zero?

Vedclass Test Series

Exam Paper Generator

Online Exam Module