Arrange S, P, As in order of increasing ionis | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The increasing order of ionization enthalpy is $As < S < P$. On moving from left to right in a period,the ionization energy generally increases. O

Vedclass · Accepted Answer

$As < S < P$

Vedclass · Answer

(C) The increasing order of ionization enthalpy is $As On moving from left to right in a period,the ionization energy generally increases. On moving down the group,the ionization energy decreases. $As$ is in the $4^{th}$ period,while $S$ and $P$ are in the $3^{rd}$ period,so $As$ has the lowest ionization energy. Between $S$ $(3p^4)$ and $P$ $(3p^3)$,$P$ has a stable half-filled $3p$ orbital,making it harder to remove an electron compared to $S$. Thus,the correct order is $As < S < P$.

Arrange $S, P, As$ in order of increasing ionisation energy.

Similar Questions

The ionisation energy of nitrogen is more than that of oxygen because :-

What is second ionization enthalpy?

Observe the following statements.
Statement $(A)$: In general,the ionisation potential value decreases on moving down in the group.
Statement $(B)$: The $1$st ionisation potential of sodium is greater than that of potassium.
Correct answer is:

The atomic numbers of $V, Cr, Mn$ and $Fe$ are $23, 24, 25$ and $26$ respectively. Which of these elements will have the highest second ionization enthalpy?

The first ionisation potential $(IP)$ of the elements $Na$,$Mg$,$Si$,$P$,$Cl$ and $Ar$ are $5.14$,$7.65$,$8.15$,$10.49$,$12.97$ and $15.76 \ eV$,respectively. The $IP$ (in $eV$) of $K$ is closest to

Vedclass Test Series

Exam Paper Generator

Online Exam Module