Arrange the given amines in decreasing order | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The basicity of amines depends on the availability of the lone pair of electrons on the nitrogen atom.$(I)$ Piperidine: The nitrogen atom is $sp^3

Vedclass · Accepted Answer

$I > II > III$

Vedclass · Answer

(A) The basicity of amines depends on the availability of the lone pair of electrons on the nitrogen atom.$(I)$ Piperidine: The nitrogen atom is $sp^3$ hybridized,and the lone pair is localized. It is a secondary aliphatic amine,making it the most basic.$(II)$ Pyridine: The nitrogen atom is $sp^2$ hybridized. The lone pair is in an $sp^2$ orbital,which is more electronegative than an $sp^3$ orbital,making the lone pair less available for donation compared to piperidine.$(III)$ Aniline: The lone pair on the nitrogen atom is involved in resonance with the benzene ring (delocalized),making it the least basic.Therefore,the decreasing order of basicity is $I > II > III$.

Arrange the given amines in decreasing order of their basicity.

Similar Questions

In the reaction shown,the structure of the product $T$ is:

Which of the following statements is correct?

$H_3CCONH_2 + Br_2 + 4NaOH \longrightarrow Y + Na_2CO_3 + 2NaBr + 2H_2O$
What is $Y$ in the above reaction?

Ammonolysis of alkyl halides followed by treatment with $NaOH$ solution can be used to prepare primary,secondary,and tertiary amines. The purpose of $NaOH$ in the reaction is:

$Ph-NH_2$ $\xrightarrow[Br_2]{HNO_2} A$ $\xrightarrow[Warm]{H_2O} B$
$B$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module