Arrange the following in decreasing order of acidic strength:
$A. F-CH_2-CH_2-COOH$
$B. Cl-CH(Cl)-CH_2-COOH$
$C. F-CH_2-COOH$
$D. Br-CH_2-CH_2-COOH$

The product of the reaction is:

In the following sequence,products $I$,$J$ and $L$ are formed. $K$ represents a reagent.
$1.$ The structure of the product $I$ is
$2.$ The structures of compounds $J$ and $K$ respectively are
$3.$ The structure of product $L$ is
Give the answer for questions $1, 2$ and $3.$

Arrange the products $I$,$II$,$III$ from the following reactions in decreasing order of their acid strength.
$A) \text{Propylbenzene} \xrightarrow[\text{ (ii) } H_3O^{+}]{\text{ (i) } KMnO_4 / OH^{-}} I$
$B) CH_3COOH \xrightarrow[\text{ (ii) } H_2O]{\text{ (i) } Br_2 / \text{red } P} II$
$C) \text{Bromobenzene}$ $\xrightarrow[\substack{\text{ (ii) } CO_2 / \text{dry ether} \\ \text{ (iii) } H_3O^{+}}]{\text{ (i) } Mg / \text{dry ether}} III$

$n$-Propanol on treatment with concentrated $HBr$ gives $P$. The product $P$ on reaction with $KCN$ gave the product $Q$. The product $Q$ on heating with aqueous acidic solution,furnished the product $R$. The product $R$ is

$CH_3MgBr$ (excess) + $EtO-C(=O)-OEt$ $\xrightarrow{(2) H^{+}}$ $(A)$; Product $(A)$ is: