Arrange the following compounds in increasing | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The equilibrium constant for hydration depends on the electrophilicity of the carbonyl carbon and steric hindrance.$1$. Aldehydes are more reactiv

Vedclass · Accepted Answer

$A < C < B < E < D$

Vedclass · Answer

(B) The equilibrium constant for hydration depends on the electrophilicity of the carbonyl carbon and steric hindrance.$1$. Aldehydes are more reactive than ketones due to less steric hindrance and lower electronic stabilization of the carbonyl carbon.$2$. Electron-withdrawing groups (like $-Cl$) increase the electrophilicity of the carbonyl carbon,thereby increasing the equilibrium constant for hydration.Comparing the compounds:$(A) CH_3COCH_3$ (Ketone,no $-I$ group)$(B) CH_3CHO$ (Aldehyde,no $-I$ group)$(C) ClCH_2COCH_3$ (Ketone with $-I$ group)$(D) HCHO$ (Smallest aldehyde,no $-I$ group)$(E) ClCH_2CHO$ (Aldehyde with $-I$ group)Order of reactivity:Ketones: $(A) Aldehydes: $(B) Combining these,the increasing order is: $(A) < (C) < (B) < (E) < (D)$.

Arrange the following compounds in increasing order of their equilibrium constants for hydration:
$(A). CH_3COCH_3, (B). CH_3CHO, (C). ClCH_2COCH_3, (D). HCHO, (E). ClCH_2CHO$

Similar Questions

What is the characteristic odor of nitrobenzene?

Aldol condensation will not be observed in

Which of the following will not give the iodoform test?

Which of the following compounds does not undergo the Cannizzaro reaction?

Compare the rate of reaction toward Beckmann rearrangement for the given oxime derivatives where $\gamma$ is: $(i) CH_3COO^-$,$(ii) ClCH_2COO^-$,$(iii) PhSO_3^-$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Arrange the following compounds in increasing order of their equilibrium constants for hydration:$(A). CH_3COCH_3, (B). CH_3CHO, (C). ClCH_2COCH_3, (D). HCHO, (E). ClCH_2CHO$