Arrange the following bonds in order of increasing ionic character,giving reasons: $N-H$,$F-H$,$C-H$,and $O-H$.
(N/A) The ionic character of a bond is directly proportional to the electronegativity difference between the two bonded atoms. The greater the difference,the more polar (ionic) the bond is.
Based on the electronegativity values,the increasing order of ionic character is:
$C-H < N-H < O-H < F-H$
| Bond | Electronegativity difference |
|---|---|
| $C-H$ | $2.5 - 2.1 = 0.4$ |
| $N-H$ | $3.0 - 2.1 = 0.9$ |
| $O-H$ | $3.5 - 2.1 = 1.4$ |
| $F-H$ | $4.0 - 2.1 = 1.9$ |
Based on the electronegativity values,the increasing order of ionic character is:
$C-H < N-H < O-H < F-H$
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