An atom with high electronegativity has:

Among the following,the pairs of elements having approximately the same electronegativity values are:
$I$. $H$ and $P$
$II$. $Be$ and $Al$
$III$. $N$ and $Cl$
$IV$. $C$ and $P$

Going from fluorine to chlorine,bromine and iodine,the electronegativity

The $EN$ (Electronegativity) of element $A$ is $E_1$ and its $IP$ (Ionization Potential) is $E_2$. Hence,the $EA$ (Electron Affinity) will be:

Given that the ionization potential and electron gain enthalpy of chlorine are $13 \ eV$ and $4 \ eV$ respectively. The electronegativity of chlorine on the Mulliken scale is approximately equal to: (in $eV$)

The molecule with the most polar bond is: