Arrange the following compounds in increasing | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The acidic strength of carboxylic acids depends on the stability of the conjugate base (carboxylate ion). Electron-withdrawing groups ($-I$ effect

Vedclass · Accepted Answer

$A < B < C < D$

Vedclass · Answer

(A) The acidic strength of carboxylic acids depends on the stability of the conjugate base (carboxylate ion). Electron-withdrawing groups ($-I$ effect) stabilize the carboxylate ion and increase acidity.The substituents attached to the $\alpha$-carbon are:$(A)$ $-H$ (no inductive effect)$(B)$ $-Ph$ (weak $-I$ effect)$(C)$ $-Br$ (stronger $-I$ effect)$(D)$ $-NO_2$ (strongest $-I$ effect)The order of the $-I$ effect is: $H Therefore,the increasing order of acidic strength is: $A < B < C < D$.

Arrange the following compounds in increasing order of their acidic strength:
$(A)$ $CH_3COOH$
$(B)$ $Ph-CH_2-COOH$
$(C)$ $Br-CH_2-COOH$
$(D)$ $O_2N-CH_2-COOH$

Similar Questions

$CH_3COOC_2H_5$ with excess of $C_2H_5MgBr$ and hydrolysis gives:

Which of the following is most acidic?

Formic acid can reduce

The acid having the highest $pK_a$ value among the following is

$CH_3CH_2COOH$ $\xrightarrow{Br_2/P} X$ $\xrightarrow{NH_3} Y$. What is $Y$ in the above reaction?

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Arrange the following compounds in increasing order of their acidic strength:$(A)$ $CH_3COOH$$(B)$ $Ph-CH_2-COOH$$(C)$ $Br-CH_2-COOH$$(D)$ $O_2N-CH_2-COOH$