Arrange the following compounds in order of i | vedclass

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(B) The dipole moment $(\mu)$ depends on the vector sum of individual bond dipoles.$(IV)$ $p$-dichlorobenzene: The two $C-Cl$ bond dipoles are equal a

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$IV < I < II < III$

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(B) The dipole moment $(\mu)$ depends on the vector sum of individual bond dipoles.$(IV)$ $p$-dichlorobenzene: The two $C-Cl$ bond dipoles are equal and opposite, so $\mu = 0$.$(I)$ Toluene: The methyl group is electron-donating, creating a small dipole moment.$(II)$ $m$-dichlorobenzene: The angle between the two $C-Cl$ bonds is $120^{\circ}$, resulting in a net dipole moment.$(III)$ $o$-dichlorobenzene: The angle between the two $C-Cl$ bonds is $60^{\circ}$, resulting in the largest net dipole moment due to the smaller angle.Thus, the correct order is: $IV < I < II < III$.

Arrange the following compounds in order of increasing dipole moment.
$(I)$ Toluene
$(II)$ $m$-dichlorobenzene
$(III)$ $o$-dichlorobenzene
$(IV)$ $p$-dichlorobenzene

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Arrange the following compounds in order of increasing dipole moment.$(I)$ Toluene$(II)$ $m$-dichlorobenzene$(III)$ $o$-dichlorobenzene$(IV)$ $p$-dichlorobenzene