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(A) The boiling points of isomeric amines follow the order: Primary $(1^{\circ})$ > Secondary $(2^{\circ})$ > Tertiary $(3^{\circ})$. This is because

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$III < I < II$

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(A) The boiling points of isomeric amines follow the order: Primary $(1^{\circ})$ > Secondary $(2^{\circ})$ > Tertiary $(3^{\circ})$. This is because primary amines $(R-NH_2)$ have two hydrogen atoms available for intermolecular hydrogen bonding,secondary amines $(R_2-NH)$ have one,and tertiary amines $(R_3-N)$ have none. $I.$ $N$-Ethylethanamine (Secondary amine,$2^{\circ}$) $II.$ Butanamine (Primary amine,$1^{\circ}$) $III.$ $N,N$-Dimethylethanamine (Tertiary amine,$3^{\circ}$) Therefore,the increasing order of boiling points is $III < I < II$.

Arrange the following in increasing order of their boiling points:
$I.$ $N$-Ethylethanamine
$II.$ Butanamine
$III.$ $N,N$-Dimethylethanamine

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Arrange the following in increasing order of their boiling points: $I.$ $N$-Ethylethanamine $II.$ Butanamine $III.$ $N,N$-Dimethylethanamine