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(A) Calculate the mass of each substance:$I$. $1$ mole of $N_2 = 1 	imes 28 \ g = 28 \ g$$II$. $0.5$ mole of $O_3 = 0.5 	imes 48 \ g = 24 \ g$$III$.

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$IV < III < II < I$

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(A) Calculate the mass of each substance:$I$. $1$ mole of $N_2 = 1 	imes 28 \ g = 28 \ g$$II$. $0.5$ mole of $O_3 = 0.5 	imes 48 \ g = 24 \ g$$III$. $3.011 	imes 10^{23}$ molecules of $O_2 = 0.5$ mole of $O_2 = 0.5 	imes 32 \ g = 16 \ g$$IV$. $0.5$ gram atom of $O = 0.5 	imes 16 \ g = 8 \ g$Comparing the masses: $8 \ g Thus, the order of increasing mass is $IV < III < II < I$.

Arrange the following in order of increasing mass:
$I$. $1$ mole of $N_2$
$II$. $0.5$ mole of $O_3$
$III$. $3.011 \times 10^{23}$ molecules of $O_2$
$IV$. $0.5$ gram atom of $O$

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Arrange the following in order of increasing mass:$I$. $1$ mole of $N_2$$II$. $0.5$ mole of $O_3$$III$. $3.011 \times 10^{23}$ molecules of $O_2$$IV$. $0.5$ gram atom of $O$