Arrange the following ligands in the order of increasing field strength.

$I$. $H_2O$	$II$. $CO$
$III$. $NH_3$	$IV$. $I^{-}$
$V$. $F^{-}$

Which one of the following complexes has the highest magnitude of crystal field splitting energy $\left(\Delta_0\right)$?

Zero value of $CFSE$ is observed in which of the following complexes?

If $[Cu(H_{2}O)_{4}]^{2+}$ absorbs light of wavelength $600 \ nm$ for $d-d$ transition,then the value of octahedral crystal field splitting energy for $[Cu(H_{2}O)_{6}]^{2+}$ will be $..... \times 10^{-21} \ J$. (Nearest Integer)
(Given: $h = 6.63 \times 10^{-34} \ Js$ and $c = 3.08 \times 10^{8} \ ms^{-1}$)

The crystal field stabilisation energy of $[Co(NH_3)_6]Cl_3$ is

Given below are two statements:
Statement $I$: Among $Zn$, $Mn$, $Sc$ and $Cu$, the energy required to remove the third valence electron is highest for $Zn$ and lowest for $Sc$.
Statement $II$: The correct order of the following complexes in terms of $CFSE$ is $[Co(H_2O)_6]^{2+} < [Co(H_2O)_6]^{3+} < [Co(en)_3]^{3+}$.