Arrange the following compounds in decreasing order of basic strength:
$(i)$ Aniline
(ii) $p$-Nitroaniline
(iii) $p$-Cyanoaniline
(iv) $p$-Toluidine

  • A
    $(i) > (ii) > (iii) > (iv)$
  • B
    $(ii) > (iii) > (i) > (iv)$
  • C
    $(iv) > (i) > (iii) > (ii)$
  • D
    $(iv) > (i) > (ii) > (iii)$

Explore More

Similar Questions

The correct order of decreasing basic strength of the following compounds is:
$(I)$ Aniline
$(II)$ $p$-Methoxyaniline
$(III)$ $p$-Nitroaniline
$(IV)$ $m$-Nitroaniline

Difficult
View Solution

The reaction between a primary amine,chloroform and a few drops of alcoholic $KOH$ is known as:

Arrange the following in decreasing order of their basic strength:
$C_6H_5NH_2, C_2H_5NH_2, (C_2H_5)_2NH, NH_3$

The following sequence of reaction on $A$ gives:

Difficult
View Solution

Which among the following compounds is a primary amine?

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo