As per molecular orbital theory,the pair of m | vedclass

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Question

(D) According to molecular orbital theory,a molecule does not exist if its bond order is $0$. The bond order is calculated as $\frac{1}{2} (N_b - N_a)

Vedclass · Accepted Answer

$Be_2, Ne_2$

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(D) According to molecular orbital theory,a molecule does not exist if its bond order is $0$. The bond order is calculated as $\frac{1}{2} (N_b - N_a)$,where $N_b$ is the number of electrons in bonding orbitals and $N_a$ is the number of electrons in anti-bonding orbitals. MoleculeBond Order$He_2$$\frac{1}{2}(2-2) = 0$$Be_2$$\frac{1}{2}(4-4) = 0$$Ne_2$$\frac{1}{2}(10-10) = 0$ Since $He_2, Be_2,$ and $Ne_2$ have a bond order of $0$,they do not exist. Therefore,the pair $Be_2$ and $Ne_2$ does not exist.

As per molecular orbital theory,the pair of molecules which do not exist is:

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