The internuclear distances in O-O bonds for O | vedclass

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(D) According to Molecular Orbital Theory,the bond order decreases as we add electrons to antibonding orbitals.The bond orders are:$O_2^+ (2.5), O_2 (

Vedclass · Accepted Answer

$1.12 \ \mathring{A}, 1.21 \ \mathring{A}, 1.30 \ \mathring{A}, 1.49 \ \mathring{A}$

Vedclass · Answer

(D) According to Molecular Orbital Theory,the bond order decreases as we add electrons to antibonding orbitals.The bond orders are:$O_2^+ (2.5), O_2 (2.0), O_2^- (1.5), O_2^{2-} (1.0)$.Since bond length is inversely proportional to bond order,the bond length increases as bond order decreases.The order of bond lengths is: $O_2^+ The corresponding bond lengths are approximately $1.12 \ \mathring{A}, 1.21 \ \mathring{A}, 1.30 \ \mathring{A}, 1.49 \ \mathring{A}$ respectively.

The internuclear distances in $O-O$ bonds for $O_2^+$,$O_2$,$O_2^-$ and $O_2^{2-}$ respectively are

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