Which of the following pairs of species have | vedclass

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(C) Let us calculate the number of unpaired electrons and bond order for each pair:$1$. $CO$ ($14$ electrons): Bond order = $3$,unpaired electrons = $

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$O_2, B_2$

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(C) Let us calculate the number of unpaired electrons and bond order for each pair:$1$. $CO$ ($14$ electrons): Bond order = $3$,unpaired electrons = $0$. $CN^{-}$ ($14$ electrons): Bond order = $3$,unpaired electrons = $0$. (Same bond order,same unpaired electrons).$2$. $O_2^{+}$ ($15$ electrons): Bond order = $2.5$,unpaired electrons = $1$. $O_2$ ($16$ electrons): Bond order = $2$,unpaired electrons = $2$. (Different bond order,different unpaired electrons).$3$. $O_2$ ($16$ electrons): Bond order = $2$,unpaired electrons = $2$. $B_2$ ($10$ electrons): Bond order = $1$,unpaired electrons = $2$. (Different bond order,same unpaired electrons).$4$. $NO^{+}$ ($14$ electrons): Bond order = $3$,unpaired electrons = $0$. $N_2$ ($14$ electrons): Bond order = $3$,unpaired electrons = $0$. (Same bond order,same unpaired electrons).Thus,the pair $O_2$ and $B_2$ have the same number of unpaired electrons $(2)$ but different bond orders ($2$ and $1$ respectively).

Which of the following pairs of species have the same number of unpaired electrons but different bond orders?

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