As shown in the figure,a metal rod makes contact with a partial circuit and completes the circuit. The circuit area is perpendicular to a magnetic field with $B = 0.15\, T$. If the resistance of the total circuit is $3\,\Omega$,the force needed to move the rod as indicated with a constant speed of $2\, ms^{-1}$ will be equal to:

  • A
    $3.75\times10^{-3}\, N$
  • B
    $2.75\times10^{-3}\, N$
  • C
    $6.57\times10^{-4}\, N$
  • D
    $4.36\times10^{-4}\, N$

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