As shown in the figure,charges $+q$ and $-q$ are placed at the vertices $B$ and $C$ of an isosceles triangle. The potential at the vertex $A$ is

  • A
    $\frac{1}{4\pi\varepsilon_0} \cdot \frac{2q}{\sqrt{a^2 + b^2}}$
  • B
    Zero
  • C
    $\frac{1}{4\pi\varepsilon_0} \cdot \frac{q}{\sqrt{a^2 + b^2}}$
  • D
    $\frac{1}{4\pi\varepsilon_0} \cdot \frac{-q}{\sqrt{a^2 + b^2}}$

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