As the velocity of light increases,the refrac | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Given: Refractive index of water $(n)$ = $4/3 = 1.33$.Speed of light in vacuum $(c)$ = $3 	imes 10^{8} 	ext{ m s}^{-1}$.We know the formula for

Vedclass · Accepted Answer

$2.25 	imes 10^{8} 	ext{ m s}^{-1}$

Vedclass · Answer

(A) Given: Refractive index of water $(n)$ = $4/3 = 1.33$.Speed of light in vacuum $(c)$ = $3 	imes 10^{8} 	ext{ m s}^{-1}$.We know the formula for refractive index is $n = c / v$,where $v$ is the speed of light in the medium.Rearranging the formula to find $v$: $v = c / n$.Substituting the values: $v = (3 	imes 10^{8}) / (4/3) = (3 	imes 10^{8} 	imes 3) / 4 = 9 	imes 10^{8} / 4 = 2.25 	imes 10^{8} 	ext{ m s}^{-1}$.Therefore,the speed of light in water is $2.25 	imes 10^{8} 	ext{ m s}^{-1}$.

As the velocity of light increases,the refractive index of the medium decreases. Light enters from air to water having a refractive index of $4/3$. Find the speed of light in water. The speed of light in vacuum is $3 \times 10^{8} \text{ m s}^{-1}$.

Similar Questions

State the sign convention used to measure the length of the image and the object.

The compound microscope consists of two convex lenses of $5 \, cm$ and $20 \, cm$ focal length. Which of them will be the objective and the eyepiece?

The absolute refractive indices of glass and water are $4/3$ and $3/2$ respectively. If the speed of light in glass is $2 \times 10^{8} \ m \ s^{-1}$,calculate the speed of light in $(i)$ vacuum,$(ii)$ water.

If the magnification of an image formed by a mirror is $(-\frac{1}{3})$,what type of mirror is it?

Where should an object be placed in front of a convex lens to obtain an image on the same side as the object?

Vedclass Test Series

Exam Paper Generator

Online Exam Module