Assertion: The HOF bond angle in HFO is highe | vedclass

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(D) The Assertion is incorrect because the $HOF$ bond angle $(101^\circ)$ is smaller than the $HOCl$ bond angle $(103^\circ)$.This occurs because fluo

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If both the Assertion and Reason are incorrect.

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(D) The Assertion is incorrect because the $HOF$ bond angle $(101^\circ)$ is smaller than the $HOCl$ bond angle $(103^\circ)$.This occurs because fluorine is more electronegative than oxygen,pulling the bonding electron pair away from the oxygen atom,which reduces the repulsion between the bonding pairs.In $HClO$,oxygen is more electronegative than chlorine,so the bonding electron pair is closer to the oxygen atom,leading to greater repulsion and a larger bond angle.The Reason is also incorrect because while oxygen is more electronegative than most halogens,it is less electronegative than fluorine $(O = 3.44, F = 3.98)$.

List-$I$ (Species)	List-$II$ (Number of lone pairs of electrons on the central atom)
$(a)$ $XeF_{2}$	$(i)$ $0$
$(b)$ $XeO_{2}F_{2}$	$(ii)$ $1$
$(c)$ $XeO_{3}F_{2}$	$(iii)$ $2$
$(d)$ $XeF_{4}$	$(iv)$ $3$

Assertion: The $HOF$ bond angle in $HFO$ is higher than the $HOCl$ bond angle in $HClO$.
Reason: Oxygen is more electronegative than halogens.

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Assertion: The $HOF$ bond angle in $HFO$ is higher than the $HOCl$ bond angle in $HClO$. Reason: Oxygen is more electronegative than halogens.